∫ (9o² + 2o)do =
trkhir -^-
trkhir -^-
Penjelasan dengan langkah-langkah:
∫ (9o² + 2o)do
[tex] = \frac{9}{2 + 1} {o}^{2 + 1} + \frac{2}{1 + 1} {o}^{1 + 1} + c[/tex]
[tex] = \frac{9}{3} {o}^{3} + \frac{2}{2} {o}^{2} + c[/tex]
[tex] = \frac{ {9o}^{3} }{3} + \frac{2 {o}^{2} }{2} + c[/tex]
[tex] = {3o}^{3} + {o}^{2} + c[/tex]
= ∫(9o² + 2o)do
= [tex]\frac{9}{2~+~1}~.~o^{2~+~1}~+~\frac{2}{1~+~1}~.~o^{1~+~1}~+~C[/tex]
= [tex]\frac{9}{3}~.~o^{3}~+~\frac{2}{2}~.~o^2~+~C[/tex]
= 3o³ + o² + C
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